if e^y+x=siny, find Dy/dx
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1/ cosy-e^y
Step-by-step explanation: d(e^y)/dx + dx/dx = d(siny)/dx
=> e^y dy/dx + 1 = cosy dy/dx
=>. cosy dy/dx - e^y dy/dx = 1
=> dy/ dx = 1/ cosy-e^y
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