Question

If E₀ represents the peak value of the voltage in an ac circuit, the r.m.s. value of the voltage will be
(a) $\frac{E_0}{\pi}sec$
(b) $\frac{E_0}{2}sec$
(c) $\frac{E_0}{\sqrt{\pi}}sec$
(d) $\frac{E_0}{\sqrt{2}}sec$

Answer 1

answer : option (d) $\frac{E_0}{\sqrt{2}}$

explanation : it is given that, E₀ be peak value of the voltage in an ac circuit,

we know, rms { root mean square } value of alternating circuit is $\frac{1}{\sqrt{2}}$ times of peak value of alternating current in an ac circuit .

e.g.,$E_{rms}=\frac{E_p}{\sqrt{2}}$

here given , $E_p=E_0$

so, $E_{rms}=\frac{E_0}{\sqrt{2}}$

hence, If E₀ represents the peak value of the voltage in an ac circuit, the r.m.s. value of the voltage will be $E_{rms}=\frac{E_0}{\sqrt{2}}$