if E1,E2,E3 are elementary events of a random experiment. p(E1)+p(E2)=X and p(E3)=1/3 then X=
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given=p(E1)+p(E2)=X
p(E3)=1/3
In an elementary event the sum of all the events is equal to 1
p(E1)+p(E2)+p(E3)=1
X+1/3=1
X=1-1/3
X=2/3
p(E3)=1/3
In an elementary event the sum of all the events is equal to 1
p(E1)+p(E2)+p(E3)=1
X+1/3=1
X=1-1/3
X=2/3
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