Question

If E1 is the ground state energy of a particle in a box, then its energy in the
second excited state E3 is *
4E1
8E1
9E1
16E1​

Answer 1

Answer:

gabar : basanti in kutto ke samne maat nachna

entertainment : kyu nahi nachhe gi haam kutto ne paise diye hai nach basanti nach

Guru Randhawa : nach meri rani

Answer 2

If E₁ is the ground state energy of a particle in a box, then its energy in the

second excited state E₃ is 9E₁

The energy of an electron rotating in an orbit is proportional to n² and inversely proportional to z² where n is the principle quantum number which represents the number of orbit of the electron and z is the atomic number of the Hydrogen like atom.

               E ∝ $\frac{n^2}{z^2}$    [E is the energy]

Here, given,

The ground state energy = E₁

The energy of second excited state = E₃

Second excited state represents the orbit number 3 and the ground state represents the orbit number 1.

  As the atom is same, so the z remains same.

∴ $\frac{E1}{ E3} = \frac{1^2}{3^2}$

⇒$\frac{E1}{E3} = \frac{1}{9}$

⇒ E₃= 9E₁