if each angle of a triangle is less than the sum of the other two show that the triangle is acute
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Answered by
1
Answer:
Step-by-step explanation:
Let ∠A<∠B+∠C. Then,
2∠A<∠A+∠B+∠C⇒2∠A<180 degree
⇒∠A<90 degree
Similarly, we obtain ∠B<90 degree
and ∠C<90 degree
=> Each angle of the triangle is less than 90° and hence it is an acute-angled triangle.
Answered by
0
Step-by-step explanation:
Let ∠A<∠B+∠C. Then,
2∠A<∠A+∠B+∠C⇒2∠A<180
∘
⇒∠A<90
∘
Similarly, we obtain ∠B<90
∘
and ∠C<90
∘
=> Each angle of the triangle is less than 90° and hence it is an acute-angled triangle.
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