if each angle of a triangle is less than the sum of the other two show that the triangle is acute angled
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LET THE ANGLES BE A, B , C
IF EACH ANGLE IS LESS THAN OTHER TWO........
A < B+C
ADDING BOTH SIDES A
A +A <A + B + C
2 A < 180 (SUM OF ALL ANGLES IN A TRIANGLE =180 )
A < 180/ 2
A < 90
SIMILARLY WE CAN FIND ANGLE B AND C SMALLER THAN 90 DEGREE....
HENCE WE CAN PROVE THAT EACH ANGLE IS THAT THE SUM OF OTHER TWO...
IF EACH ANGLE IS LESS THAN OTHER TWO........
A < B+C
ADDING BOTH SIDES A
A +A <A + B + C
2 A < 180 (SUM OF ALL ANGLES IN A TRIANGLE =180 )
A < 180/ 2
A < 90
SIMILARLY WE CAN FIND ANGLE B AND C SMALLER THAN 90 DEGREE....
HENCE WE CAN PROVE THAT EACH ANGLE IS THAT THE SUM OF OTHER TWO...
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