If each edge of a cube is doubled :
1) how many times will its surface area increase ?
2) how many times will its volume increase ?
Answers
Answered by
10
Let the edge of cube be a
Surface area = 6a^2
Volume = a^3
When edge is doubled,
New Edge = 2a
New Surface area = 6 (2a)^2
= 6 × 4 a^2
= 24 a^2
New Volume = ( 2a)^3 = 8a^3
Number of times surface area increased = 24a^2 / 6a ^2 = 4
Number of times Volume increased = 8a^3/a^3
= 8
Surface area = 6a^2
Volume = a^3
When edge is doubled,
New Edge = 2a
New Surface area = 6 (2a)^2
= 6 × 4 a^2
= 24 a^2
New Volume = ( 2a)^3 = 8a^3
Number of times surface area increased = 24a^2 / 6a ^2 = 4
Number of times Volume increased = 8a^3/a^3
= 8
Answered by
0
Step-by-step explanation:
Surface area of cube=6a2
Is sides of cube is doubled
New surface area is =6×4a2
Divide 2 by 1
=24a2surfaceareaofcube1surfaceareaofcube2=6a224a2=4times
Surface area increased four times
Volume of cube= a3
Volume of new cube= (2a)3
=8a3
Divide 2 by 1
volumeofcubevolumeofnewcube=a38a3
Volume increased 8 times
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