if each edge of a cube is in-
creased by 25%, then the per-
centage increase in its surface
area is
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Answer:
Original surface area = 6a²
New side = 125a/100 = 5a/4
New surface area = 6*(5a/4)²
= 75a²/8
Surface area increased = 75a²/8- 6a²
= 75a²-48a²/8
= 27a²/8
% increase in surface area = 27a²/8 × 1/6a² × 100
= 56.25%
Hope it helps you
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