if each edge of a cube is increased by 25%, then find the percentage increased in its surface area
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Hlw mate
To find the % increase in surface area, consider:
A cube has 6 square surfaces. The surface area of each surface is the edge length [S] squared (remember L*W?).
So, the surface area of a cube is 6*S^2 = 6*S*S.
If the length of each edge is increased by 25%, the new surface area is 6*(1.25*S)*(1.25*S)
Or, 6*( (5/4)*S )*( (5/4)*S ) = 6* (25/16) * S^2
= (75/8) * S^2 this is a surface area of 9.375 * S^2
And as a ratio, the increase is
( 9.375*S*S ) / ( 6*S*S) = 1.5625 times as large
As a %, the surface area would increase by 56.25%.
Hope it helpful
To find the % increase in surface area, consider:
A cube has 6 square surfaces. The surface area of each surface is the edge length [S] squared (remember L*W?).
So, the surface area of a cube is 6*S^2 = 6*S*S.
If the length of each edge is increased by 25%, the new surface area is 6*(1.25*S)*(1.25*S)
Or, 6*( (5/4)*S )*( (5/4)*S ) = 6* (25/16) * S^2
= (75/8) * S^2 this is a surface area of 9.375 * S^2
And as a ratio, the increase is
( 9.375*S*S ) / ( 6*S*S) = 1.5625 times as large
As a %, the surface area would increase by 56.25%.
Hope it helpful
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