if each edge of a cube is increased by 50% find the percentage increase in the surface area
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Let a= initial length of edge=1
A= final length of edge=1.5
S1=6a*a=6*1*1=6
S2=6*1.5*1.5=6*2.25
S2-S1=6(2.25-1)=6*1.25
%increase=(s2-s1)*100/s1
=6*1.25*100/6
=125%
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