If each edge of a cube is increased by 50 percent then by what percentage its surface area & volume increased?
Answers
Let the original length of the edge = x
The length of the length after 50% increase is 1.5x
Find the original surface area:
Area = 6 x side²
Area = 6 x²
Find the increased in surface area:
Area = 6 x side²
Area = 6 (1.5x)²
Area = 13.5 x²
Find the increased in area:
Percentage increase = new area / original area x 100
Percentage increase = (13.5x² /6x² ) x 100 = 225%
Find the original volume:
Volume = Length³
Volume = x³
Find the new volume:
Volume = Length³
Volume = (1.5x)³ = 3.375 x³
Find the increased in volume:
Percentage increased = (3.375x³ ÷ x³) x 100 = 337.5%
Answer: The surface area is increased by 225% and the volume is increased by 337.5%
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SHORT CUT:
Increased in area = (increased in length)²
Increased in area = (1.5)²
Increased in area = 2.25 times or 225%
Increased in volume = (increased in length)³
Increased in area = (1.5)³
Increased in area = 3.375 times or 337.5%