Question

if each edge of a cuboid area of surface area s is doubled what will happen to surface area of the new cuboid​

Answer 1

Step-by-step explanation:

HEY MATE.......

Let l,b,h be the length, breadth, height of the first cuboid.

Let L,B,H be the length, breadth, height of the new cuboid.

We know that,

L=2l

B=2b

H=2h

Surface area of the first cuboid S=2(lb+bh+hl)

Surface area of new cuboid S =2(LB+BH+HI)

=2(4lb+4bh+4hl) =4[2(lb+bh+hl)]

=4S

∴ The surface area of the new cuboid is 4S.

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