Question

If each edge of a cuboid of surface area 54 CM square is doubled then square area of new cuboid is

Answer 1

TSA of original Cuboid = lbh

                               lbh = 54                ..............(1)

As each edge of a cuboid gets doubled then, l = 2 l, b = 2 b, h = 2 h

Then, TSA of new cuboid = 2 l × 2 b × 2 h

                                         = 2 × 2 × 2(lbh)

 From (1)                           = 8(54) 

                                          = 432 cm²
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Answer 2

Surface area of cuboid = lbh
Here ,
lbh = 54 cm square
According to the question each edge is doubled.
L = 2l
B = 2b
H = 2h
New surface area = 2 × 2 × 2( lbh)
= 8 (54)
= 432 cm square

Hope it helps.