Question

If each edge of a cuboid of surface area 54cm2 is doubled then surface area of new cuboid is :

Answer 1

The surface Area of cuboid is 6(edge)^2=54
Edge=√9=3cm
A/Q,
New edge=6cm.
Surface Area=6(6)^2

=6(36)

=216cm^2.

Hope this will help u

Answer 2

$\bold{216 \mathrm{cm}^{2}}$ is the new cuboid’s surface area.

To find:

The value of surface area of the new cuboids.

Solution:

Formula for “Surface Area of Cuboids” is =2(lb+bh+hl)

Let,

l=b=h=x.

Such that Surface Area $=2(x \times x+x \times x+x \times x)$

$=2\left(3 \times x^{2}\right)$

$=6 \times x^{2}$

Given the surface area $=54 \mathrm{cm}^{2}$ , such that

$6 \times x^{2}=54$

$x^{2}=9$

X =3, such that edge value of cuboid is 3cm.

To find the new value cuboid if the edge is doubles, such that surface area,

$=6 \times x^{2}$

$=6 \times 6 \times 6$

$=216 \mathrm{cm}^{2}$