If each edge of a cuboid of surface area S is doubled, then surface area of the new cuboid is (b) 4S (c) 6S (d) 8S (a) 2 S
Answers
Answered by
13
Thanks for your question...
Your required answer :
- Let edge of cuboid are l , b and h.
- Surface area = 2 ( lb + bh + hl )
A.T.Q. :
- 2 ( 4lb + 4bh + 4hl )
- 2 × 4 (lb + bh + hl )
- 4 × 2( lb + bh + hl )
- 4 × Surface Area
Thus , surface area will increased by 4 times.
Option B is the correct answer.
Brainliest Please
Answered by
1
Step-by-step explanation:
Let edge of cuboid are l , b and h.
Surface area = 2 ( lb + bh + hl )
A.T.Q. :
2 ( 4lb + 4bh + 4hl )
2 × 4 (lb + bh + hl )
4 × 2( lb + bh + hl )
4 × Surface Area
Thus , surface area will increased by 4 times.
Option B is the correct answer.
Similar questions