if each interior angle of a regular polygon is 162°,what is the number of sides that it has
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Sum of all the interior angles of any convex polygon of 'n' sides is (2n-4)*90°…(1)
Given that the polygon is regular polygon.we know that regular polygon has all sides equal in length and all angles equal in length and given that each angle is 162° .So sum of n angles is n*162 …(2)
Equating (1)&(2),
(2n-4)*90=n*162
180n-360=162n
18n=360
n=360/18=20
Hence the number of sides of given regular polygon each of interior angle 162° is 20
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not understanding the problem
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