Question

if each of radius of the base and height of a cone be doubled, then the volume of it will be
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Answer 1

Answer:

doubled

Step-by-step explanation:

beause base and height of a cone doubled

Answer 2

Answer:

Step-by-step explanation:

Volume of a cone = $\frac{1}{3  }  \pi r^{2} h$

when radius and height are doubled,

volume of the cone = $\frac{1}{3}  \pi  (2r)^{2}  (2h)$

                                 = $\frac{1}{3}   \pi  (4r ^{2} ) (2h)$

                                 = $8 [\frac{1}{3}  \pi  r^{2}  h ]$

                                 = 8 x (initial volume)

Therefore the volume of the cone becomes 8 times when radius and height are doubled.