Question

if each of the dimensions of a rectangle is increased by 100 percent then the area is increased by​

Answer 1

Step-by-step explanation:

Thus when width and length increased by 100% the area of it increases by 4 times that is 400%.

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. Therefore

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lb

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lbIncrease=4lb−lb=3lb

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lbIncrease=4lb−lb=3lbIncrease percent=

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lbIncrease=4lb−lb=3lbIncrease percent= lb

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lbIncrease=4lb−lb=3lbIncrease percent= lb3lb

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lbIncrease=4lb−lb=3lbIncrease percent= lb3lb

b'If l and b are the dimensions of a rectangle, then l increases by 100%of l and b increases by 100% of b. ThereforeArea=(l+ 100100 l)×(b+ 100100 b) =(2l)×(2b)=4lbIncrease=4lb−lb=3lbIncrease percent= lb3lb ×100=300%'

Answer 2

Answer:

300%

Step-by-step explanation:

ok........................