If each of the points (a,4),(-2,b) lies on the
line joining the points (2,-1),(5,-3),then the
point (a,b) lies on line
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Step-by-step explanation:
Equation of the line passing through the point (2,−1) and (5,−3)
x-2/y+1=5-2/-3+1
⇒−2x+4=3y+3
⇒2x+3y−1=0....(i)
Also (a,4) and (−2,b) lies on the line (i)
2a+3(4)−1=0
⇒2a+12−1=0
⇒2a=−11
⇒a=-11/2
2(−2)+3b−1=0
⇒−4+3b−1=0⇒3b=5
⇒b= 5/3
2x+6y+1=0 is the required line.
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