Question

If each orbital can hold a maximum of 3 electrons.
The number of elements in 2nd period of periodic
table (long form) is
(1) 27
(2) 9
(4) 12
(3) 18

Answer 1

Answer:

12 is the correct answer!!!!!

Explanation:

First we need to calculate:

i) No. of subshells ii) No. of orbitals iii) No. of elements  

Formula to calculate no. of subshell

1) No. of period is even :  $\frac{n+2}{2}$

2) No. of period is odd :  $\frac{n+1}{2}$

​ ∴  $\frac{n+2}{2}$⇒n=2

Thus no. of orbitals in various subshell are:

For n=2 we have only s & p orbitals

s has 1 orbital

p has 3 orbital

∴ no. of orbital =4

It is given that each orbital can have a maximum of 3 electrons.

Thus maximum no. of electrons =4×3=12  

Hence, the no. of elements = 12

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