Question

if each orbital can hold maximum 2 e-, total of of elements is 8th period will be divided by 15 is

Answer 1

Answer:

Explanation:

Well, this is kind of open to interpretation... but if I interpreted it correctly, I get  

27

elements, compared to the original  

18

elements, in the 4th period of the periodic table.

(If you already knew that the number of electrons allowed in a given orbital is derived from the properties of electrons, and NOT of the orbitals themselves, the answer quickly follows.)

PRELIMINARY THINGS

I think there's a typo in the question... I looked this up elsewhere, and it's probably...

If each orbital can hold a maximum of 3 electrons, the number of elements in the 4th period of the periodic table (long form) is...?

Also, note that this is entirely theoretical, as all electrons only have two possible spins ( m s  =  ±  1 2 ) in a given orbital, and no two electrons can share the same quantum state (Pauli Exclusion Principle); that restricts each orbital to contain only two electrons in real life.

That aside, when we suppose three electrons are "allowed" in a single orbital (assuming the other three quantum numbers are as normal), we suddenly "allow"  50 %more elements in a given quantum level.

(It's not really why the periodic table was arranged historically, but... I suppose that's what the intent of this question was...)

Answer 2

Chemistry

Classification of Elements and Periodicity in Properties

Modern Periodic Law and Periodic Table

If each orbital can hold a ...

CHEMISTRY

Asked on December 26, 2019 byKanhaiya Jindal

If each orbital can hold a maximum of 3 electrons. The number of elements in 2nd period of the periodic table (long form) will be:

A

27

B

9

C

18

D

12

HARD

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ANSWER

First we need to calculate:

i) No. of subshells ii) No. of orbitals iii) No. of elements 

Formula to calculate no. of subshell

1) No. of period is even : 2(n+2)

2) No. of period is odd : 2(n+1)

∴2(n+2)⇒n=2

Thus no. of orbitals in various subshell are:

For n=2 we have only s & p orbitals

s has 1 orbital

p has 3 orbital

∴ no. of orbital =4

It is given that each orbital can have a maximum of 3 electrons.

Thus maximum no. of electrons =4×3=12 

Hence, the no. of elements = 12

Option D is correct.