If each resistance in the figure is of 9 2 then reading of ammeter is
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Answer:
1 A
Explanation:
Net resistance of resistors after ammeter is
Since they are connected in parallel then
1/R'=1/9+1/9+1/9+1/9+1/9
R'=9/5 Ω
Similarly net resistance of resistors before ammeter is
R"=9/4 Ω
Net resistance of the circuit is
R'+R"= 9/4+9/5
R=9Ω
By ohm's law
I=V/R
I=9/9
I=1 A
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