Question

if each side a square be increased by 10%,the percentage increase in area

Answer 1

Answer is 21%<br>

Let the side of square be = [tex]l[\tex]m <br>

Area [tex]A = {l}^2[\tex]m²<br>

[tex]l' = l+ 0.1l= 1.1l[\tex]<br>

[tex]A' = {1.1l}^2[\tex]<br>

[tex]A' = 1.21 {m}^2[\tex]<br>

increase = [tex]A' - A = .21l[\tex]<br>

Which is exactly 21%

Answer 2

Let take the side of a square as s.,

Then the area1 is = s^2

Given is increasing the side by 10%

= (1+10/100)*s

= 1.1s

Now area2 is.,

= (1.1s)^2

= 1.21*s^2

((area2-area1)/area1)*100 = ((1.21*s^2-s^2)/s^2)*100

= (s^2(1.21-1)/s^2)*100

= 0.21*100

= 21

Therefore 21% increase.,ANS