Question

If each side of a cube increase 50% by length,then what is the percentage increase in total surface area of the cube?​

Answer 1

$\huge\bold\green{Solution}$

$\huge\boxed{\fcolorbox{purple}{ink}{GIVEN:}}$

• side of a cube increase 50% by length

$\huge\bold\red{Consider}$

• Let the original side be y then

• Original surface area S=6y²

$\huge\boxed{\fcolorbox{red}{ink}{Then:}}$

• When side is increased by 50%, side becomes 3/2y then

$Surface \: \: area \: \: s= \frac{27}{2} {y}^{2}$

$\huge\boxed{\dag\sf\red{THEREFORE}\dag}$

$Surface \: \: area \: \: is \: \: \: \: increases \: \: by \: x= \\ \\ \\ x= \frac{ \frac{27}{2} {y}^{2} - 6{y}^{2} }{6 {y}^{2} } \times 100 \\ \\ = 125\%$

$\huge\boxed{\dag\sf\red{ANSWER}\dag}$

• The percentage increase in total surface area of the cube by 125 percent

$\huge\boxed{\dag\sf\red{Thanks}\dag}$