Question

If each side of a cube is decreased by 10% then it's surface area is decreased by?

Answer 1

Answer:

19% this is the correct answer the other one was bs.

Step-by-step explanation:

Answer 2

Answer:

It's surface area is decreased by 19%.

Step-by-step explanation:

As per the data given in the question,

We assume,

Let the side of the cube be $10x$

So, surface area will be = $6a^{2} = 6\times (10x)^{2} = 600x^{2}$

Now, by decreasing sides by 10%.

New side will be = $9x$

So, surface area will be = $6a^{2} = 6\times (9x)^{2} = 486x^{2}$

Thus, the decrease in surface are is = $600x^{2} -486x^{2} =114x^{2}$

And the decrease percentage is:

$=\frac{114x^{2} }{600x^{2} }\times 100\\=19\%$

Hence, It's surface area is decreased by 19%.

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