if each side of a cube is half then find the percent increase in its volume
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Answered by
3
Ans : 125%
Solution:
Initial Volume of cube = a^3 ( a= side of cube)
Final volume = (3a/2)^3 = (27a^3 / 8)
Since each edge length is increased by 50%
Percentage of increase in volume
= (increase in volume / initial volume) × 100
= (( (27/8 -1) a^3) / a^3 ) × 100
= ( 19 / 8 )× 100
= 237.5%
Solution:
Initial Volume of cube = a^3 ( a= side of cube)
Final volume = (3a/2)^3 = (27a^3 / 8)
Since each edge length is increased by 50%
Percentage of increase in volume
= (increase in volume / initial volume) × 100
= (( (27/8 -1) a^3) / a^3 ) × 100
= ( 19 / 8 )× 100
= 237.5%
singarapusreehanth6:
hi dear
Answered by
1
HEY AA BUDDY HERE IS UR SOLUTION !!!!
Let each side of a cube = a unit
Surface area = 6 a^2 sq.unit.
New length of each side
=a+50%of a
=3a/2 unit
New surface area
=6(3a/2)^2=6×9a^2/4=27a^2/2
Increase in surface area
=27a^2/2–6a^2=15a^2/2
% increase in s/area
=(15a^2)×100/2×6a^2
=15×100/2×6
=5×25
125 % , Answer
Hope u like my process !!
》》BE BRAINLY《《
^_^
Let each side of a cube = a unit
Surface area = 6 a^2 sq.unit.
New length of each side
=a+50%of a
=3a/2 unit
New surface area
=6(3a/2)^2=6×9a^2/4=27a^2/2
Increase in surface area
=27a^2/2–6a^2=15a^2/2
% increase in s/area
=(15a^2)×100/2×6a^2
=15×100/2×6
=5×25
125 % , Answer
Hope u like my process !!
》》BE BRAINLY《《
^_^
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