Question

if each side of a cube is increased by 50% find the percentage increase in its surface​

Answer 1

Answer:

let original area be x

original side be 100

new side be = 150

so,new area = 1.5 x

there has been 1.5%increase in the surface area

Answer 2

Answer:

50%

Step-by-step explanation:

let the side of the cube be x

so now the increased side will be x+50/100×x

=x+x/2

=3x/2

so first it's surface area was 6x^2

now it is 6(3x/2)^2=6(9x^2/4)=3×9x^2/2

=27x^2/2

so first area was 6x^2 and let it be 100%

so,6x^2. =. 100%

-------- --------

27x^2/2. y

so,2 will become reciprocal and

2×6x^2. =. 100%

-----------. --------

27x^2. y

=2/3=100/y

=100×3/2=y

=100×1.5=y

=150%=y

so there is 50% change in the surface area of the cube

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