if each side of a cube is increased by 50% find the percentage increase in its surface
Answers
Answered by
0
Answer:
let original area be x
original side be 100
new side be = 150
so,new area = 1.5 x
there has been 1.5%increase in the surface area
Answered by
0
Answer:
50%
Step-by-step explanation:
let the side of the cube be x
so now the increased side will be x+50/100×x
=x+x/2
=3x/2
so first it's surface area was 6x^2
now it is 6(3x/2)^2=6(9x^2/4)=3×9x^2/2
=27x^2/2
so first area was 6x^2 and let it be 100%
so,6x^2. =. 100%
-------- --------
27x^2/2. y
so,2 will become reciprocal and
2×6x^2. =. 100%
-----------. --------
27x^2. y
=2/3=100/y
=100×3/2=y
=100×1.5=y
=150%=y
so there is 50% change in the surface area of the cube
PLEASE MARK MY ANSWER AS BRAINLIEST BECAUSE YOU WILL GET POINTS FOR THAT
Similar questions