Question

if each side of a cube is increased by 50% find the percentage increase in its surface area

Answer 1

I hope this is the answer.. Just tried to help you out :)

Answer 2

Answer:

The surface area increased by 125%.

Step-by-step explanation:

Let the initial side length be x. Then the surface area of cube is

$A_1=6x^2$

If each side of a cube is increased by 50%, then the new side length is

$x+\frac{50}{100}x=x+0.5x=1.5x$

The surface area of new cube is

$A_2=6(1.5x)^2$

$A_2=6(1.5)^2x^2$

$A_2=13.5x^2$

The percentage increase in its surface area is

$P=\frac{A_2-A_1}{A_1}\times 100$

$P=\frac{13.5x^2-6x^2}{6x^2}\times 100$

$P=\frac{7.5}{6}\times 100=125%$

Therefore the surface area increased by 125%.