Math, asked by BhupenRay, 6 months ago

if each side of a cube is increased by 50% find the percentage increases in its surface area. ​

Answers

Answered by namratakargutkar78
3

Answer:

After 50% increase, each edge of the cube becomes 150/100 of the original. Thus, the surface area of the cube becomes (150/100)^2 = 225/100 of the original. Hence, increase in perecentage of surface area = (225-100) = 125% .

Answered by lonenissar101
0

Let side of cube=2

Surface Area=6side^2=6×2^2=24

Increase in side=50%of 2=1

Side of new cube=2+1=3

Surface Area=6side^2=6×3^2=54

Increase in Surface Area=54-24=30

increased percentage=30/24×100=125%

Similar questions