Question

if each side of a cube is increased by 50% find the percentage increase in its surface area​

Answer 1

initial side =a

surface area =6a^2

when side is increased by 50%

side = a(1+50/100)

=a(1+1/2)

=a(3/2)

=3/2a

surface area=6*3/2*3/2a^2

=27/2a^2

increase=27/2a^2-6a^2

=15a^2/2

increase%= 15a^2/6a^2*2*100%

= 125%