If each side of a square is increased by 10 it's area will be increased by
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Answered by
115
Heya !
Here's your answer.. ⬇
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Let the side of square = s
Area of square = s²
Given that side of square is increased by 10%.
side by increasing 10% = ( 1 + 1/100 )
new side of square = 1.1s
Area of new square = ( 1.1s )²
= 1.21s²
Total increase area = New square area - area of square
= 1.21s² - s²
= 0.21s²
Now, percentage of increased area
=( 0.21s²/ s² ) × 100
= 0.21/100
= 21%
Hence, area of square will increase by 21% .
_______________________________
Hope it helps..
Thanks :)
Here's your answer.. ⬇
__________________________
Let the side of square = s
Area of square = s²
Given that side of square is increased by 10%.
side by increasing 10% = ( 1 + 1/100 )
new side of square = 1.1s
Area of new square = ( 1.1s )²
= 1.21s²
Total increase area = New square area - area of square
= 1.21s² - s²
= 0.21s²
Now, percentage of increased area
=( 0.21s²/ s² ) × 100
= 0.21/100
= 21%
Hence, area of square will increase by 21% .
_______________________________
Hope it helps..
Thanks :)
Answered by
45
Answer:
Here's your answer.. ⬇
Step-by-step explanation:
Let the side of square = s
Area of square = s²
Given that side of square is increased by 10%.
side by increasing 10% = ( 1 + 1/100 )
new side of square = 1.1s
Area of new square = ( 1.1s )²
= 1.21s²
Total increase area = New square area - area of square
= 1.21s² - s²
= 0.21s²
Now, percentage of increased area
=( 0.21s²/ s² ) × 100
= 0.21/100
= 21%
Hence, area of square will increase by 21% .
_______________________________
Hope it helps..
Thanks :)
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