Question

If each side of a triangle is doubled, then find the percentage increase in the area of triangle ...............​

Answer 1

Answer:

are the attached image

KVian here

which KV?

Answer 2

Answer:

300%

Step-by-step explanation:

let initial side length = a

⇒ area of triangle = $\sqrt{3} /4$ a²

after doubling,

side length = 2a

⇒ area of triangle = $\sqrt{3} a^2$

percentage increase

= $[(\sqrt{3} a^2 - \sqrt{3} /4 a^2) / (\sqrt{3} /4a^2)]$ × 100

= $3\sqrt{3}/\sqrt{3}$ × 100

= 300%