Question

IF each side of an isoceles triangle is
$3 \sqrt{2}$
and base is 8 then the area of triangle is!?
​

Answer 1

$\huge\red{Question:}$

IF each side of an isoceles triangle is

$3 \sqrt{2}$

and base is 8 then the area of triangle is ?Fonts for Android and iPhone - www.fontskeyboard.com/share-now

$\huge\green{Answer->}$

Given :

Each side of iscosceles triangle:

$3\sqrt{2}$

Base = 8

We know that,

By Pythagorus theorem,

${base}^{2} + {height}^{2} = {hypotenus}^{2}$

Let height be x, then,

$3\sqrt{2} = {4}^{2} + {x}^{2}$

$18 = 16 + {x}^{2}$

${x}^{2} = 18 - 16 = 2$

$x \: = \sqrt{2}$

We know that ,

Area = 1/2 × base × height

= 1/2 × 8 × $\sqrt{2}$

= 4 $\sqrt{2}$ cm