Question

If each side of an isosceles triangle is 3√2 and
Its base 8 cm, then find the area of an
isosceles triangle​

Answer 1

Answer:

side=3√2 cm

base=8cm

area=1/2×8×3√2

=4×3√2

=12√2

Answer 2

Step-by-step explanation:

side of an isosceles triangle is 3√2 cm

base =8 cm

if we draw perpendicular from top on base then we get height.this perpendicular divides the triangle into two equal right angle triangle s of base 8/2 cm=4 cm

so height^2=hypotenuse^2-base^2

=(3√2)^2-(4)^2

=18-16=2

so, height=√2

so area of the triangle

=1/2.base.height

=1/2.4.√2 sq cm

=2√2sq cm