if each side of triangle is triple then find percentage increased in its area?
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Let the initial side be a units
Area = (√3)a²/4 sq. units
Now, side is tripled,
new side, a' = 3a
New area = (√3)(3a)²/4
=9×[(√3)a²/4]
=9×(initial area)
Increase in area = 9×(initial area) - (initial area) = 8 ×(initial area)
% increase = (increase/initial area)×100
=[8 ×(initial area)/(initial area)]×100
= 800 %
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