Physics, asked by Mritun, 1 year ago

If Earth somehow contracted to  of its current volume instantly (through some magical internal forces), while keeping its shape and mass, then how long would a day be?(No useless answers please!)

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Answers

Answered by mrityun
2

Since only internal forces are shrinking it, the angular momentum of Earth will remain constant.


Volume is proportional to r³


Therefore, 1/8th volume = (1/8)r⅓ = r/2


Angular momentum (L) = IW , where I is the moment of inertia and W is the angular velocity


I proportional to mr²


If radius is halved, I will become ¼th, thus W should become 4 times.


Hence, the earth will spin 4 times as fast, making the time of a day = 24/4 = 6 hours

☺️


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Answered by vikashpatnaik2009
0

Answer:

Since only internal forces are shrinking it, the angular momentum of Earth will remain constant.

Volume is proportional to r³

Therefore, 1/8th volume = (1/8)r⅓ = r/2

Angular momentum (L) = IW , where I is the moment of inertia and W is the angular velocity

I proportional to mr²

If radius is halved, I will become ¼th, thus W should become 4 times.

Hence, the earth will spin 4 times as fast, making the time of a day = 24/4 = 6 hours

☺️

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