Question

if earth were to rotate on its own axis such that the weight of a person at the equator becomes half the weight at the poles then its time period of ratation is (g=acceleration due to gravity near the poles and R is the radius of earth )(Ignore equatorial bulge)​

Answer 1

Answer:

2r 2R/g

Explanation:

Answer 2

Answer:

Let weight of the person be mg and the angular speed of the earth be ω.

Thus weight of the person at poles=mg

Weight of the person at equator=mg−mω

2

R

⟹mg=2(mg−mω

2

R)

⟹ω

2

R=

2

g

⟹ω=

2R

g

Thus time period of earth's rotation=

ω

2π

=2π

g

2R