Question

If efficiency of carnot cycle engine is 0.75. If the cycle is reversed, its coefficient of performance as heat refrigerator is ? Solution

Answer 1

Explanation:

Efficiency of Carnot cycle (η)= 0.75

By reversing the Carnot cycle we can have either heat pump or refrigerator.

COP of heat pump = 1 / η = 1.33

COP of refrigerator = COP of heat pump – 1 = 0.33

Answer 2

The coefficient of performance as heat refrigerator is 0.33.

Explanation:

The coefficient of performance of a Carnot refrigerator cycle is given as

$COP_R=\frac{1-\eta}{\eta}$              (for reversed cycle)

Here, $\eta$  is the efficiency of Carnot cycle engine.

Given $\eta=0.75$

Substitute the given values, we get

$COP_R=\frac{1-0.75}{0.75}$

$COP_R=0.333$

Thus, the coefficient of performance as heat refrigerator is 0.33.

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