Question

if effort =5kg and machanical advantage of a lever 9 what is the load​

Answer 1

Explanation:

Mechanical advantage M.A.=

Load arm

Effort arm

Given,

Load arm = 5 cm

Effort arm = 9 cm

Substituting the values in the formula we get,

M.A. = \dfrac{9}{5} \\[0.5em] \Rightarrow M.A. = 1.8 \\[0.5em]M.A.=

5

9

⇒M.A.=1.8

Relation between mechanical advantage, efficiency and velocity ratio is

M.A. = \eta \times V.R. \\[0.5em]M.A.=η×V.R.

Given, η = 100% = 1

So,

M.A. = 1 \times V.R. \\[0.5em]M.A.=1×V.R.

Therefore, Mechanical advantage = Velocity ratio = 1.8

(d) When efficiency reduces to 50%, its mechanical advantage reduces however, its velocity ratio remains the same. So,

M.A. = 0.5 x 1.8 = 0.9

V.R. = 1.8