If efg and h are respectively the midpoints of the sides of a parallelogram abcd show that
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if abcd is a parallelogram then. join HF which mid point of ad and BC then we have
ar(∆hgf) =1÷2ar (hdcf)eqn 1
ar(
ar(∆hgf) =1÷2ar (hdcf)eqn 1
ar(
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