if eight ship out of 10 arrives safely find the probability that at least one would arrive safely out of 5 ship
a) 3211/3225
b)3421/3512
C) 3124/3125
D)3522/3560
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Answer:
3124/3125
Step-by-step explanation:
because the probability of 8 coming safely out of 10 is 8/10 so 1 coming safely out of 5 would be 4/5 as x/5=8/10 so we get x as 4 by equating
10x=40 and x= 40
now the options are a b c d and we have to find which among them is the correct option by checking whether its a multiple of 4/5 and clearly there is only one as only 312 is divisible by 4 and subsequently it is the correct answer
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