If electri flux is 0 then is it necessary that no charge is present inside gaussian surface.
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hey,..here is your answer friend..
I learned that the vector flux through any closed surface is always 0. So if you have a sphere(closed surface) and you put it in an uniform electric field, then the total flux is 0.
However, the Gauss's law states that the electric field flux through a closed surface equals the enclosed charge divided by the permitivity of free space. Shouldn't it be 0? What am I misunderstanding here?
Any explanation will be appreciated.
I learned that the vector flux through any closed surface is always 0. So if you have a sphere(closed surface) and you put it in an uniform electric field, then the total flux is 0.
However, the Gauss's law states that the electric field flux through a closed surface equals the enclosed charge divided by the permitivity of free space. Shouldn't it be 0? What am I misunderstanding here?
Any explanation will be appreciated.
Answered by
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No, it is not necessary that there would be no charge in the gaussian surface! Because electric flux of the surface is 1/Enot times the net charge enclosed inside the surface! So it may possible that there are a number of charges available inside the surface but the net charge becomes zero!!
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