Question

If electric field between 2 large parallel plates is 2N/C and charge on 2 plates are 10C and 3C then force on one of the plates is :
1. 20N
2. 13N
3. 60/7N
4. 7/2N

Answer 1

Answer:

HEY MATE!

YOUR ANSWER IS ABOVE .

YOUR RIGHT OPTION IS 60/7 N.

Answer 2

The force on one of the plates is $\frac{60}{7}$ N. Third option is the right option.

Explanation:

Given:

electric field b/w 2 large plates = 2 N/C

Charges on two plates = 10C and 3C.

               We know,     E = E₁ + E₂

                                     q  = $\frac{q_{1} }{2AE_{o} } + \frac{q_{2} }{2A E_{o}}$

                                     2 = $\frac{7}{AE_{o} }$

                                     A$E_{o}$ = 3.5

Now, force on one of the plates.

                   $F_{21} = \frac{q_{1} \times q_{2} }{2AE_{o} }$

                      = $\frac{10}{2} \times \frac{2}{3.5}$

After solving the above calculation, the answer is given below.

                      = $\frac{60}{7}$ N