Question

If electrode potential of cell at 298 K temperature is 2.36 V. Write cell reaction and calculate the half-cell potential. Mg(s) | Mg2+ (1M) || H+ (1M) | H2(g) (1 bar) | Pt(s)

Answer 1

Answer:

According to Nerast Equation-

Emn+/m=E∘mn+/m−n0.0591log[mn+]1

EZn2+/zn=Ezn2+/zn−20.0591log[zn2+]1

⇒−0.76−20.0591log0.110

⇒−0.76−20.0591

⇒2−1.52−0.0591

⇒EZn2+/zn=−0.789volt