If electronegativity values of element X and Y are
3.8 and 1.8 respectively, then ionic percentage of
compound XY is :
(1) 50 (2) 46 (3) 64 (4) 36
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Given: Electro-negativity values of element X and Y are 3.8 and 1.8 respectively.
To find: Ionic percentage of compound XY?
Solution:
- Now we have given electro-negativity values of element X and Y are 3.8 and 1.8.
- Now, the formula to calculate Ionic percentage is :
Ionic % = 16 x ΔEN + 3.5 x (ΔEN)²
- Here ΔEN = (3.8 - 1.8) = 2
16(2) + 3.5(2)²
32 + 3.5(4)
32 + 14
46%
Answer:
So the ionic % of compound XY is 46%.
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