if electrons are caused to fall through a potential difference of 10^5V, determine their
final speed if they were initially at rest.
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There is no way to tell since the units of the potential are not included.
If “volts” then the final kinetic energy is 100keV … you can use the kinetic energy equation to get the speed as a fraction of the speed of light:
K=12(mc2)(v/c)2 … approx for low speeds.
For an electron, mc^2 = 511keV
I get about v = 0.6c … but I could be wrong
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