Question

If end of diameter are (1,2) and (-1,-2) then coordinate of centre is _________

Answer 1

$\mathsf{Given \: ends \: of \: diameter \: are \: (1,2) ; (-1,-2)}$

$\mathsf{Let \: p(x_{1},y_{1}) \: = \: (1,2)} \\ \mathsf{p(x_{2},y_{2}) \: = \: (-1,-2)}$

To find centre :- $\large\mathsf{(\frac{x_{1}+x_{2}}{2} \: , \: \frac{y_{1}+y_{2}}{2})}$

$\mathsf{(\frac{1+( - 1)}{2} \: , \: \frac{2+( - 2)}{2})} \\ =\mathsf{(\frac{0}{2} \: , \: \frac{0}{2})} \\ = (0 , 0)$

$\mathsf\red{\therefore \: coordinate \: of \: centre \: is \: (0,0)}$

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