If end term of an ap is within bracket 2 n + 1 write the sum of its first 3 terms
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1st term = 2n+1
= 2(1)+1= 2+1= 3
second term = 2(2)+1
= 4+1= 5
third term =2(3)+1= 7
sum of first three term
S3= n/2 ×2a +(n-1)×D
3/2× 2(3)+(3-1) × 2
3/2×6+2(2)
3/2× 6+4
3/2×10
3×5 = 15
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