Question

if energy of a ball falling from Hight of 100 m is 70%of its initial energy how high will it rebound.

Answer 1

Answer:

• At each collision with the floor, the ball loses one-tenth of its speed. Plot the speed-time graph of its motion t= 0 to t = 12s. Hint: We could use Newton's equations of motion to find the final velocity before the first collision with the floor.

Step-by-step explanation:

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Answer 2

Given That The Ball Is Dropped From A Height,h1=100m

Potential Energy At h1=mgh1

Therefore The Potential Energy At h1=m×100×100=100mJ

On striking the ground level, the ball looses 70%of its initial energy:

i.e.100070×100mJ=70mJ

The energy left on striking the ground=100mJ−70mJ=60mJ

So the final energy of the ball, mgh2=60mJ

i.eh2=1060=6m

Hence the ball will bounce back to a height of 6m.