Question

If enor in the measurement of radius of a
sphere is 1%, What will be the error in the
measlerement of volceme ?​

Answer 1

Explanation:

volume of sphere is 4/3πr^3

error is radius is = 1 %

So,

4/3π are constant...

according to measurement of error in power formula

r^3 = 3r

• % r = 1
• so 3×1=3%

Answer 2

$=~Volume~ =~\dfrac{4π{R}^{3}}{3}$

$=~\dfrac{ΔV}{V}~×~100~=~3\dfrac{∆R}{R}~×~100$

$=~3~×~\dfrac{1}{100}~×~100$

$=~3$

∴ Percentage error in volume is 3%

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$\bold\red{Hope~it~helps~✌}$